How to Solve Spiral Problem

My solution for spiral problem.

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package main   import (     "fmt" )   func spiral(height, width, row, col int) []int {     a := createSlice(height, width)     result := []int{}     r := row - 1     c := col - 1     result = append(result, a[r][c])     x := 1     for z := 0; (height * width) != len(result); z++ {         for i := 0; i < x; i++ {             r, c = up(r, c)             if !outOfBoundary(height, width, r, c) {                 result = append(result, a[r][c])             }         }         for i := 0; i < x; i++ {             r, c = left(r, c)             if !outOfBoundary(height, width, r, c) {                 result = append(result, a[r][c])             }         }         x += 1         for i := 0; i < x; i++ {             r, c = down(r, c)             if !outOfBoundary(height, width, r, c) {                 result = append(result, a[r][c])             }         }         for i := 0; i < x; i++ {             r, c = right(r, c)             if !outOfBoundary(height, width, r, c) {                 result = append(result, a[r][c])             }         }         x += 1     }     return result }   func outOfBoundary(height, width, row, col int) bool {     return !((row >= 0 && row < height) && (col >= 0 && col < width)) }   func left(row, col int) (int, int) {     return row, col - 1 }   func right(row, col int) (int, int) {     return row, col + 1 }   func up(row, col int) (int, int) {     return row - 1, col }   func down(row, col int) (int, int) {     return row + 1, col }   func createSlice(height, width int) [][]int {     a := make([][]int, height)     n := 1     for i := 0; i < height; i++ {         a[i] = make([]int, width)         for j := 0; j < width; j++ {             a[i][j] = n             n += 1         }     }     return a }   func main() {     fmt.Println(spiral(5, 5, 3, 3))     fmt.Println(spiral(2, 4, 1, 2))     fmt.Println(spiral(5, 5, 4, 2)) }